Django Filter

[Nirali Supe]

Hello,

class JobsFilter(filters.FilterSet):
class Meta:
model = Jobs
fields = {'id': ['exact', 'lt', 'gt'],
'runs': ['exact', 'in', 'lt', 'gt'],
}
class JobsViewSet(viewsets.ModelViewSet):
"""
List all Entries, or create a new one.
"""
queryset = Jobs.objects.all()
serializer_class = JobsSerializer
filter_backends = (filters.DjangoFilterBackend,)
filter_class = JobsFilter

The following url is working:
http://127.0.0.1:8000/suite-runs-by-job?id__lt=2&runs__gt=30


But I need the url in the following format:
http://127.0.0.1:8000/suite-runs-by-job?id=lt:2&runs=gt:30

Is there a way I can do that?

[Jason]

django filters uses django's lookup format to execute the filtering on the
models. while I suspect what you want can be done, its going to require
you to make your own query parser ad transform it to the format filters
expects for the lookups. Is that really a good way to spend your time?

Post by Nirali Supe
Hello,
model = Jobs
fields = {'id': ['exact', 'lt', 'gt'],
'runs': ['exact', 'in', 'lt', 'gt'],
}
"""
List all Entries, or create a new one.
"""
queryset = Jobs.objects.all()
serializer_class = JobsSerializer
filter_backends = (filters.DjangoFilterBackend,)
filter_class = JobsFilter
http://127.0.0.1:8000/suite-runs-by-job?id__lt=2&runs__gt=30
http://127.0.0.1:8000/suite-runs-by-job?id=lt:2&runs=gt:30
Is there a way I can do that?